What is the foci (((x^2))/(27))-(((y-3)^2))/(36)=1 ?

The foci (((x^2))/(27))-(((y-3)^2))/(36)=1 is (3sqrt(7),3),(-3sqrt(7),3)

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foci (((x^2))/(27))-(((y-3)^2))/(36)=1

foci

(\frac{( x ^{2} )}{27}) - \frac{( ( y - 3 ) ^{2} )}{36} = 1

(37, 3), (- 37, 3)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{27} - \frac{( y - 3 ) ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 3), a = 33, b = 6

(0 + c, 3), (0 - c, 3)

Compute

c :

c = (33)^{2} + 6^{2} : 37

(0 + 37, 3), (0 - 37, 3)

Refine

(37, 3), (- 37, 3)

\frac{( x - 7 ) ^{2}}{25} - \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{5} - \frac{y ^{2}}{7} = 1

\frac{( x - 6 ) ^{2}}{25} - \frac{( y + 4 ) ^{2}}{9} = 1

3 x^{2} - 2 y^{2} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{25} = 1

What is the foci (((x^2))/(27))-(((y-3)^2))/(36)=1 ?
The foci (((x^2))/(27))-(((y-3)^2))/(36)=1 is (3sqrt(7),3),(-3sqrt(7),3)