What is the foci (y^2)/(25)-(x^2)/(25)=1 ?

The foci (y^2)/(25)-(x^2)/(25)=1 is (0,5sqrt(2)),(0,-5sqrt(2))

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foci (y^2)/(25)-(x^2)/(25)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{25} = 1

(0, 52), (0, - 52)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 5^{2} : 52

(0, 0 + 52), (0, 0 - 52)

Refine

(0, 52), (0, - 52)

\frac{( x - 6 ) ^{2}}{10} - \frac{( y + 2 ) ^{2}}{17} = 1

\frac{( x - 1 ) ^{2}}{1 2 ^{2}} - \frac{( y - 11 ) ^{2}}{8 ^{2}} = 1

\frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{12} = 1

\frac{( y - 3 ) ^{2}}{7} - \frac{( x + 6 ) ^{2}}{42} = 1

\frac{x ^{2}}{3} - \frac{y ^{2}}{3} = 1

What is the foci (y^2)/(25)-(x^2)/(25)=1 ?
The foci (y^2)/(25)-(x^2)/(25)=1 is (0,5sqrt(2)),(0,-5sqrt(2))