What is the foci (y^2)/(225)-(x^2)/(64)=1 ?

The foci (y^2)/(225)-(x^2)/(64)=1 is (0,17),(0,-17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2)/(225)-(x^2)/(64)=1

foci

\frac{y ^{2}}{225} - \frac{x ^{2}}{64} = 1

(0, 17), (0, - 17)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{225} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 15, b = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 5^{2} + 8^{2} : 17

(0, 0 + 17), (0, 0 - 17)

Refine

(0, 17), (0, - 17)

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

x^{2} - y^{2} = 13

\frac{( y ) ^{2}}{81} - \frac{( x ) ^{2}}{121} = 1

What is the foci (y^2)/(225)-(x^2)/(64)=1 ?
The foci (y^2)/(225)-(x^2)/(64)=1 is (0,17),(0,-17)