What is the foci (x^2)/(100)-(y^2)/(49)=1 ?

The foci (x^2)/(100)-(y^2)/(49)=1 is (sqrt(149),0),(-sqrt(149),0)

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foci (x^2)/(100)-(y^2)/(49)=1

foci

\frac{x ^{2}}{100} - \frac{y ^{2}}{49} = 1

(149, 0), (- 149, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{100} - \frac{y ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 10, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 0^{2} + 7^{2} : 149

(0 + 149, 0), (0 - 149, 0)

Refine

(149, 0), (- 149, 0)

\frac{( y - ( - 2 ) ) ^{2}}{9} - \frac{( x - 5 ) ^{2}}{27} = 1

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( 3 x - 0 ) ^{2}}{90} = 1

- \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{16} = 1

\frac{( x - 0 ) ^{2}}{16} - \frac{( y - 0 ) ^{2}}{9} = 1

What is the foci (x^2)/(100)-(y^2)/(49)=1 ?
The foci (x^2)/(100)-(y^2)/(49)=1 is (sqrt(149),0),(-sqrt(149),0)