y^2+4x=7

Solution

y^{2} + 4 x = 7

(h, k) = (\frac{7}{4}, 0), p = - 1

Solution steps

y^{2} + 4 x = 7

Rewrite

y^{2} + 4 x = 7

in the standard form:

4 (- 1) (x - \frac{7}{4}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{4}, 0), p = - 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

9 x^{2} - 16 y^{2} = 144

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

x = 2 y^{2}

f (x) = x^{2} - 6 x + 1

What is y^2+4x=7 ?
The solution to y^2+4x=7 is Parabola with (h,k)=(7/4 ,0),p=-1