What is the asymptotes of (y^2}{16}-\frac{x^2)/9 =1 ?

The asymptotes of (y^2}{16}-\frac{x^2)/9 =1 is y=(4x)/3 ,\quad y=-(4x)/3

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asymptotes of (y^2}{16}-\frac{x^2)/9 =1

asymptotes

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

y = \frac{4 x}{3}, y = - \frac{4 x}{3}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

y = \frac{4}{3} (x - 0) + 0, y = - \frac{4}{3} (x - 0) + 0

Refine

y = \frac{4 x}{3}, y = - \frac{4 x}{3}

x = 2 y^{2}

f (x) = x^{2} - 6 x + 1

x^{2} + \frac{y ^{2}}{64} = 1

x^{2} - y = 0

y^{2} = - 4 x

What is the asymptotes of (y^2}{16}-\frac{x^2)/9 =1 ?
The asymptotes of (y^2}{16}-\frac{x^2)/9 =1 is y=(4x)/3 ,\quad y=-(4x)/3