What is the axis x^2+(y^2)/(64)=1 ?

The axis x^2+(y^2)/(64)=1 is semi-major axis b=8, semi-minor axis a=1

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axis x^2+(y^2)/(64)=1

axis

x^{2} + \frac{y ^{2}}{64} = 1

semi - major axis b = 8, semi - minor axis a = 1

Solution steps

x^{2} + \frac{y ^{2}}{64} = 1

Rewrite

x^{2} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 1

x^{2} - y = 0

y^{2} = - 4 x

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

f (x) = 3 x^{2} - 6 x + 4

16 x^{2} - 9 y^{2} = 144

What is the axis x^2+(y^2)/(64)=1 ?
The axis x^2+(y^2)/(64)=1 is semi-major axis b=8, semi-minor axis a=1