顶点 16x^2-9y^2=144

解答

顶点

16 x^{2} - 9 y^{2} = 144

(3, 0), (- 3, 0)

求解步骤

(h + a, k), (h - a, k)

计算双曲线性质

16 x^{2} - 9 y^{2} = 144 :

左右开口双曲线，

(h, k) = (0, 0), a = 3, b = 4

(0 + 3, 0), (0 - 3, 0)

整理后得

(3, 0), (- 3, 0)

y^{2} = 8 x

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0