What is (x^2)/9+(y^2)/(25)=1 ?

The solution to (x^2)/9+(y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=3,b=5

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(x^2)/9+(y^2)/(25)=1

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 3, b = 5

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 3

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{49} = 1

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

f (x) = x^{2} - 10 x + 24

What is (x^2)/9+(y^2)/(25)=1 ?
The solution to (x^2)/9+(y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=3,b=5