What is the area (x^2)/(a^2)+(y^2)/(b^2)=1 ?

The area (x^2)/(a^2)+(y^2)/(b^2)=1 is A=piab

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area (x^2)/(a^2)+(y^2)/(b^2)=1

area

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

A = πab

Solution steps

A = π \cdot a \cdot b

Calculate ellipse properties:

(h, k) = (0, 0), a = a, b = b

A = πab

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

f (x) = x^{2} - 10 x + 24

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

f (x) = x^{2} - 8 x + 12

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

What is the area (x^2)/(a^2)+(y^2)/(b^2)=1 ?
The area (x^2)/(a^2)+(y^2)/(b^2)=1 is A=piab