What is the asymptotes of (y^2)/(36)-(x^2)/(64)=1 ?

The asymptotes of (y^2)/(36)-(x^2)/(64)=1 is y=(3x)/4 ,\quad y=-(3x)/4

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asymptotes of (y^2)/(36)-(x^2)/(64)=1

asymptotes

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 8

y = \frac{6}{8} (x - 0) + 0, y = - \frac{6}{8} (x - 0) + 0

Refine

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

3 x^{2} - y^{2} = 11

9 x^{2} + 16 y^{2} = 144

x^{2} + y^{2} = 10

x^{2} + \frac{y ^{2}}{25} = 1

What is the asymptotes of (y^2)/(36)-(x^2)/(64)=1 ?
The asymptotes of (y^2)/(36)-(x^2)/(64)=1 is y=(3x)/4 ,\quad y=-(3x)/4