What is the foci x^2+(y^2)/(25)=1 ?

The foci x^2+(y^2)/(25)=1 is (0,2sqrt(6)),(0,-2sqrt(6))

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foci x^2+(y^2)/(25)=1

foci

x^{2} + \frac{y ^{2}}{25} = 1

(0, 26), (0, - 26)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

x^{2} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 1^{2} : 26

(0, 0 + 26), (0, 0 - 26)

Refine

(0, 26), (0, - 26)

(x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

9 y^{2} - 4 x^{2} = 36

x^{2} - y^{2} \geq 1

x^{2} = - 28 y

What is the foci x^2+(y^2)/(25)=1 ?
The foci x^2+(y^2)/(25)=1 is (0,2sqrt(6)),(0,-2sqrt(6))