What is (x+2)^2+((y+4)^2)/(1/4)=1 ?

The solution to (x+2)^2+((y+4)^2)/(1/4)=1 is Ellipse with (h,k)=(-2,-4),a=1,b= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+2)^2+((y+4)^2)/(1/4)=1

(x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

(h, k) = (- 2, - 4), a = 1, b = \frac{1}{2}

Solution steps

(x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

Rewrite

(x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{1 ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, - 4), a = 1, b = \frac{1}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 2, - 4), a = 1, b = \frac{1}{2}

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

9 y^{2} - 4 x^{2} = 36

x^{2} - y^{2} \geq 1

x^{2} = - 28 y

f (x) = - x^{2} + 4 x - 3

What is (x+2)^2+((y+4)^2)/(1/4)=1 ?
The solution to (x+2)^2+((y+4)^2)/(1/4)=1 is Ellipse with (h,k)=(-2,-4),a=1,b= 1/2