What is the asymptotes of 9y^2-4x^2=36 ?

The asymptotes of 9y^2-4x^2=36 is y=(2x)/3 ,\quad y=-(2x)/3

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asymptotes of 9y^2-4x^2=36

asymptotes

9 y^{2} - 4 x^{2} = 36

y = \frac{2 x}{3}, y = - \frac{2 x}{3}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

9 y^{2} - 4 x^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

y = \frac{2}{3} (x - 0) + 0, y = - \frac{2}{3} (x - 0) + 0

Refine

y = \frac{2 x}{3}, y = - \frac{2 x}{3}

x^{2} - y^{2} \geq 1

x^{2} = - 28 y

f (x) = - x^{2} + 4 x - 3

3 y + 4 x = - 2 x^{2} - 14

x^{2} = 20 y

What is the asymptotes of 9y^2-4x^2=36 ?
The asymptotes of 9y^2-4x^2=36 is y=(2x)/3 ,\quad y=-(2x)/3