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Popular >

foci x^2=20y

Solution

foci

x^{2} = 20 y

Solution

(0, 5)

Solution steps

Rewrite

x^{2} = 20 y

in the standard form:

4 \cdot 5 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 5

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + 5)

Refine

(0, 5)

Popular Examples

(x^2)/(169)+(y^2)/(25)=1

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

asymptotes of (y^2)/9-(x^2)/4 =1 asymptotes

\frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1

2x^2-6x+2y^2+2y=45

2 x^{2} - 6 x + 2 y^{2} + 2 y = 45

foci x^2-y^2=6 foci

x^{2} - y^{2} = 6

vertices f(x)=x^2+4x+1 vertices

f (x) = x^{2} + 4 x + 1

Frequently Asked Questions (FAQ)

What is the foci x^2=20y ?
The foci x^2=20y is (0,5)