What is the foci x^2-y^2=6 ?

The foci x^2-y^2=6 is (2sqrt(3),0),(-2sqrt(3),0)

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foci x^2-y^2=6

foci

x^{2} - y^{2} = 6

(23, 0), (- 23, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 6 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 6^{2} : 23

(0 + 23, 0), (0 - 23, 0)

Refine

(23, 0), (- 23, 0)

f (x) = x^{2} + 4 x + 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

x - 2 = \frac{1}{8} (y + 1)^{2}

y = 2 x^{2}

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1