What is (x^2}{16}-\frac{y^2)/9 =1 ?

The solution to (x^2}{16}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=4,b=3

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(x^2}{16}-\frac{y^2)/9 =1

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 3

9 y^{2} - 4 x^{2} = 36

x^{2} - y^{2} \geq 1

x^{2} = - 28 y

f (x) = - x^{2} + 4 x - 3

3 y + 4 x = - 2 x^{2} - 14

What is (x^2}{16}-\frac{y^2)/9 =1 ?
The solution to (x^2}{16}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=4,b=3