What is the vertices ((x-3)^2)/5+((y-1)^2)/(15)=1 ?

The vertices ((x-3)^2)/5+((y-1)^2)/(15)=1 is (3,1+sqrt(15)),(3,1-sqrt(15))

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vertices ((x-3)^2)/5+((y-1)^2)/(15)=1

vertices

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

(3, 1 + 15), (3, 1 - 15)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1 :

Ellipse with center

(h, k) = (3, 1), b = 15, a = 5

(3, 1 + 15), (3, 1 - 15)

3 x^{2} - y^{2} = 11

9 x^{2} + 16 y^{2} = 144

x^{2} + y^{2} = 10

x^{2} + \frac{y ^{2}}{25} = 1

(x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

What is the vertices ((x-3)^2)/5+((y-1)^2)/(15)=1 ?
The vertices ((x-3)^2)/5+((y-1)^2)/(15)=1 is (3,1+sqrt(15)),(3,1-sqrt(15))