What is the center ((x+4)^2)/9-((y-3)^2)/(25)=1 ?

The center ((x+4)^2)/9-((y-3)^2)/(25)=1 is (-4,3)

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center ((x+4)^2)/9-((y-3)^2)/(25)=1

center

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

(- 4, 3)

Solution steps

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} - \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 3), a = 3, b = 5

And the center is:

(- 4, 3)

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

16 x^{2} - 9 y^{2} + 64 x + 54 y - 161 = 0

x^{2} - y^{2} < 1

What is the center ((x+4)^2)/9-((y-3)^2)/(25)=1 ?
The center ((x+4)^2)/9-((y-3)^2)/(25)=1 is (-4,3)