What is the center 5x^2-2y^2+10x-12y=23 ?

The center 5x^2-2y^2+10x-12y=23 is (-1,-3)

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center 5x^2-2y^2+10x-12y=23

center

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

(- 1, - 3)

Solution steps

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

Rewrite

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{( 2 ) ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - 3), a = 2, b = 5

And the center is:

(- 1, - 3)

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

16 y^{2} - x^{2} + 2 x + 64 y + 47 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

- x^{2} + y^{2} = 1

What is the center 5x^2-2y^2+10x-12y=23 ?
The center 5x^2-2y^2+10x-12y=23 is (-1,-3)