What is the center (x^2)/(25)-(y^2)/(64)=1 ?

The center (x^2)/(25)-(y^2)/(64)=1 is (0,0)

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center (x^2)/(25)-(y^2)/(64)=1

center

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 8

And the center is:

(0, 0)

4 x^{2} - 9 y^{2} = 36

4 x^{2} - \frac{1}{2} y^{2} + 8 x - 2 y = 2

4 x^{2} - 9 y^{2} + 3 x + 18 y + 91 = 0

\frac{( x + 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

9 x^{2} - 25 y^{2} = 225

What is the center (x^2)/(25)-(y^2)/(64)=1 ?
The center (x^2)/(25)-(y^2)/(64)=1 is (0,0)