What is the center ((x+5)^2)/(36)-(y^2)/(64)=1 ?

The center ((x+5)^2)/(36)-(y^2)/(64)=1 is (-5,0)

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center ((x+5)^2)/(36)-(y^2)/(64)=1

center

\frac{( x + 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

(- 5, 0)

Solution steps

\frac{( x + 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 0), a = 6, b = 8

And the center is:

(- 5, 0)

9 x^{2} - 25 y^{2} = 225

- 4 x^{2} + y^{2} + 16 x + 12 y + 16 = 0

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

x^{2} - y^{2} = 6

What is the center ((x+5)^2)/(36)-(y^2)/(64)=1 ?
The center ((x+5)^2)/(36)-(y^2)/(64)=1 is (-5,0)