What is the center (x^2)/4-(y^2)/6 =-1 ?

The center (x^2)/4-(y^2)/6 =-1 is (0,0)

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center (x^2)/4-(y^2)/6 =-1

center

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

(0, 0)

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 6 ) ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 2

And the center is:

(0, 0)

4 x^{2} + 8 x - 4 y^{2} + 12 y - 3 = 0

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

+ 0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

- 16 x^{2} + 25 y^{2} - 64 x - 150 y - 239 = 0

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

What is the center (x^2)/4-(y^2)/6 =-1 ?
The center (x^2)/4-(y^2)/6 =-1 is (0,0)