What is the center ((x-5)^2)/1-((y-4)^2)/1 =1 ?

The center ((x-5)^2)/1-((y-4)^2)/1 =1 is (5,4)

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center ((x-5)^2)/1-((y-4)^2)/1 =1

center

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

(5, 4)

Solution steps

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{1 ^{2}} - \frac{( y - 4 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 4), a = 1, b = 1

And the center is:

(5, 4)

+ 0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

- 16 x^{2} + 25 y^{2} - 64 x - 150 y - 239 = 0

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

2 y^{2} - x^{2} - y + x = 0

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 9

What is the center ((x-5)^2)/1-((y-4)^2)/1 =1 ?
The center ((x-5)^2)/1-((y-4)^2)/1 =1 is (5,4)