What is the center ((y+5)^2)/9-((x-3)^2)/(25)=9 ?

The center ((y+5)^2)/9-((x-3)^2)/(25)=9 is (3,-5)

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center ((y+5)^2)/9-((x-3)^2)/(25)=9

center

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 9

(3, - 5)

Solution steps

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 9

Rewrite

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 9

in the form of a standard hyperbola equation

\frac{( y - ( - 5 ) ) ^{2}}{9 ^{2}} - \frac{( x - 3 ) ^{2}}{1 5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 5), a = 9, b = 15

And the center is:

(3, - 5)

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

\frac{( y - 7 ) ^{2}}{9} - (x + 4)^{2} = 1

2 y^{2} - 9 x^{2} - 18 x + 20 + 5 = 0

x^{2} + 36 y - 32 x - y^{2} = 75

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

What is the center ((y+5)^2)/9-((x-3)^2)/(25)=9 ?
The center ((y+5)^2)/9-((x-3)^2)/(25)=9 is (3,-5)