What is the center 4x^2+9y^2+3x-18y^2+37=0 ?

The center 4x^2+9y^2+3x-18y^2+37=0 is (-3/8 ,0)

Popular >

center 4x^2+9y^2+3x-18y^2+37=0

center

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

(- \frac{3}{8}, 0)

Solution steps

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

Rewrite

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{583}{12} ) ^{2}} - \frac{( x - ( - \frac{3}{8} ) ) ^{2}}{( \frac{583}{8} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- \frac{3}{8}, 0), a = \frac{583}{12}, b = \frac{583}{8}

And the center is:

(- \frac{3}{8}, 0)

9 y^{2} - x^{2} - 36 y - 6 x + 18 = 0

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{9} = 1

\frac{( y - ( - 2 ) ) ^{2}}{9} - \frac{( x - 5 ) ^{2}}{27} = 1

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4

4 x^{2} - 8 y^{2} = 3

What is the center 4x^2+9y^2+3x-18y^2+37=0 ?
The center 4x^2+9y^2+3x-18y^2+37=0 is (-3/8 ,0)