What is the center ((y-3)^2}{11}-\frac{(x+1)^2)/5 =1 ?

The center ((y-3)^2}{11}-\frac{(x+1)^2)/5 =1 is (-1,3)

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center ((y-3)^2}{11}-\frac{(x+1)^2)/5 =1

center

\frac{( y - 3 ) ^{2}}{11} - \frac{( x + 1 ) ^{2}}{5} = 1

(- 1, 3)

Solution steps

\frac{( y - 3 ) ^{2}}{11} - \frac{( x + 1 ) ^{2}}{5} = 1

Rewrite

\frac{( y - 3 ) ^{2}}{11} - \frac{( x + 1 ) ^{2}}{5} = 1

in the form of a standard hyperbola equation

\frac{( y - 3 ) ^{2}}{( 11 ) ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 3), a = 11, b = 5

And the center is:

(- 1, 3)

(\frac{y - 1}{9})^{2} - (\frac{x - 2}{4})^{2} = 1

x^{2} - 5 y^{2} - 6 x - 10 y - 1 = 0

4 y^{2} = 4 x^{2} + 12 y - 69 + 32 x

4 x^{2} - 12 y^{2} - 24 x + 24 y + 51 = 0

y^{2} - x^{2} = \frac{4}{25}

What is the center ((y-3)^2}{11}-\frac{(x+1)^2)/5 =1 ?
The center ((y-3)^2}{11}-\frac{(x+1)^2)/5 =1 is (-1,3)