What is the center ((x+10)^2)/(36)-((y-3)^2)/(100)=1 ?

The center ((x+10)^2)/(36)-((y-3)^2)/(100)=1 is (-10,3)

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center ((x+10)^2)/(36)-((y-3)^2)/(100)=1

center

\frac{( x + 10 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{100} = 1

(- 10, 3)

Solution steps

\frac{( x + 10 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{100} = 1

Rewrite

\frac{( x + 10 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{100} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 10 ) ) ^{2}}{6 ^{2}} - \frac{( y - 3 ) ^{2}}{1 0 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 10, 3), a = 6, b = 10

And the center is:

(- 10, 3)

\frac{( y + 5 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{9} = 1

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

y^{2} - 2 x^{2} = 1

- 9 x^{2} + 16 y^{2} - 90 x + 32 y - 353 = 0

25 x^{2} - 16 y^{2} + 50 x - 32 y - 391 = 0

What is the center ((x+10)^2)/(36)-((y-3)^2)/(100)=1 ?
The center ((x+10)^2)/(36)-((y-3)^2)/(100)=1 is (-10,3)