What is the center y^2-x^2= 1/25 ?

The center y^2-x^2= 1/25 is (0,0)

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center y^2-x^2= 1/25

center

y^{2} - x^{2} = \frac{1}{25}

(0, 0)

Solution steps

y^{2} - x^{2} = \frac{1}{25}

Rewrite

y^{2} - x^{2} = \frac{1}{25}

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{5}, b = \frac{1}{5}

And the center is:

(0, 0)

\frac{1}{144} x^{2} - \frac{1}{196} y^{2} = 1

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0^{2}

\frac{( x + 1 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{25} = 1

10 x^{2} - 25 y^{2} = 100

x^{2} - y^{2} - 8 x - 2 y - 19 = 0