What is the eccentricity 9x^2-25y^2=225 ?

The eccentricity 9x^2-25y^2=225 is (sqrt(34))/5

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eccentricity 9x^2-25y^2=225

eccentricity

9 x^{2} - 25 y^{2} = 225

\frac{34}{5}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

9 x^{2} - 25 y^{2} = 225 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 3

= \frac{5 ^{2} + 3 ^{2}}{5}

Refine

= \frac{34}{5}

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

x^{2} - y^{2} < 1

What is the eccentricity 9x^2-25y^2=225 ?
The eccentricity 9x^2-25y^2=225 is (sqrt(34))/5