What is (x^2}{25}+\frac{y^2)/9 =1 ?

The solution to (x^2}{25}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=5,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2}{25}+\frac{y^2)/9 =1

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 5, b = 3

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 3

y^{2} = 16 x

(x - 3)^{2} + (y + 5)^{2} = 16

y^{2} - 8 x - 16 = 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

y^{2} - 4 x^{2} + 4 x - 2 y - 4 = 0

What is (x^2}{25}+\frac{y^2)/9 =1 ?
The solution to (x^2}{25}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=5,b=3