What is y^2-8x-16=0 ?

The solution to y^2-8x-16=0 is Parabola with (h,k)=(-2,0),p=2

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y^2-8x-16=0

y^{2} - 8 x - 16 = 0

(h, k) = (- 2, 0), p = 2

Solution steps

y^{2} - 8 x - 16 = 0

Rewrite

y^{2} - 8 x - 16 = 0

in the standard form:

4 \cdot 2 (x - (- 2)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 0), p = 2

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

y^{2} - 4 x^{2} + 4 x - 2 y - 4 = 0

x^{2} + y^{2} + 2 x = 0

y^{2} = - 4 x

y^{2} - \frac{x ^{2}}{9} = 1

What is y^2-8x-16=0 ?
The solution to y^2-8x-16=0 is Parabola with (h,k)=(-2,0),p=2