What is x^2+y^2+2x=0 ?

The solution to x^2+y^2+2x=0 is Circle with (a,b)=(-1,0),r=1

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x^2+y^2+2x=0

x^{2} + y^{2} + 2 x = 0

(a, b) = (- 1, 0), r = 1

Solution steps

x^{2} + y^{2} + 2 x = 0

Rewrite

x^{2} + y^{2} + 2 x = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 1

y^{2} = - 4 x

y^{2} - \frac{x ^{2}}{9} = 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

What is x^2+y^2+2x=0 ?
The solution to x^2+y^2+2x=0 is Circle with (a,b)=(-1,0),r=1