What is (x^2)/9-(y^2)/(64)=1 ?

The solution to (x^2)/9-(y^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=3,b=8

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(x^2)/9-(y^2)/(64)=1

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

(h, k) = (0, 0), a = 3, b = 8

Solution steps

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 8

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

What is (x^2)/9-(y^2)/(64)=1 ?
The solution to (x^2)/9-(y^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=3,b=8