What is the foci (x^2)/(16)-(y^2)/(36)=1 ?

The foci (x^2)/(16)-(y^2)/(36)=1 is (2sqrt(13),0),(-2sqrt(13),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(16)-(y^2)/(36)=1

foci

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

(213, 0), (- 213, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} + 6^{2} : 213

(0 + 213, 0), (0 - 213, 0)

Refine

(213, 0), (- 213, 0)

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

y^{2} - 6 y - 4 x + 5 = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{16} = 1

16 x^{2} + 9 y^{2} = 144

f (x) = x^{2} + 4 x - 1

What is the foci (x^2)/(16)-(y^2)/(36)=1 ?
The foci (x^2)/(16)-(y^2)/(36)=1 is (2sqrt(13),0),(-2sqrt(13),0)