What is y^2-6y-4x+5=0 ?

The solution to y^2-6y-4x+5=0 is Parabola with (h,k)=(-1,3),p=1

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y^2-6y-4x+5=0

y^{2} - 6 y - 4 x + 5 = 0

(h, k) = (- 1, 3), p = 1

Solution steps

y^{2} - 6 y - 4 x + 5 = 0

Rewrite

y^{2} - 6 y - 4 x + 5 = 0

in the standard form

4 \cdot 1 \cdot (x - (- 1)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 3), p = 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{16} = 1

16 x^{2} + 9 y^{2} = 144

f (x) = x^{2} + 4 x - 1

(x - h)^{2} = 4 p (y - k)

x^{2} + (y - 1)^{2} = 1

What is y^2-6y-4x+5=0 ?
The solution to y^2-6y-4x+5=0 is Parabola with (h,k)=(-1,3),p=1