What is (x-h)^2=4p(y-k) ?

The solution to (x-h)^2=4p(y-k) is Parabola with (h,k)=(h,k),p=p

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(x-h)^2=4p(y-k)

(x - h)^{2} = 4 p (y - k)

(h, k) = (h, k), p = p

Solution steps

(x - h)^{2} = 4 p (y - k)

Rewrite

(x - h)^{2} = 4 p (y - k)

in the standard form:

4 p (y - k) = (x - h)^{2}

Therefore parabola properties are:

(h, k) = (h, k), p = p

x^{2} + (y - 1)^{2} = 1

x = y^{2} + 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

9 x^{2} - 4 y^{2} - 72 x = 0

f (x) = 2 x^{2} - x - 6

What is (x-h)^2=4p(y-k) ?
The solution to (x-h)^2=4p(y-k) is Parabola with (h,k)=(h,k),p=p