What is the center 16x^2+9y^2=144 ?

The center 16x^2+9y^2=144 is (0,0)

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center 16x^2+9y^2=144

center

16 x^{2} + 9 y^{2} = 144

(0, 0)

Solution steps

16 x^{2} + 9 y^{2} = 144

Rewrite

16 x^{2} + 9 y^{2} = 144

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 3

And the center is:

(0, 0)

f (x) = x^{2} + 4 x - 1

(x - h)^{2} = 4 p (y - k)

x^{2} + (y - 1)^{2} = 1

x = y^{2} + 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1