What is the vertices 9x^2-4y^2-72x=0 ?

The vertices 9x^2-4y^2-72x=0 is (8,0),(0,0)

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vertices 9x^2-4y^2-72x=0

vertices

9 x^{2} - 4 y^{2} - 72 x = 0

(8, 0), (0, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} - 72 x = 0 :

Right-left Hyperbola with

(h, k) = (4, 0), a = 4, b = 6

(4 + 4, 0), (4 - 4, 0)

Refine

(8, 0), (0, 0)

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} = 144

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1

x^{2} + y^{2} = 7

What is the vertices 9x^2-4y^2-72x=0 ?
The vertices 9x^2-4y^2-72x=0 is (8,0),(0,0)