What is the axis (x^2)/(25)+(y^2)/(16)=1 ?

The axis (x^2)/(25)+(y^2)/(16)=1 is semi-major axis a=5, semi-minor axis b=4

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axis (x^2)/(25)+(y^2)/(16)=1

axis

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

semi - major axis a = 5, semi - minor axis b = 4

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

F = \frac{m v ^{2}}{r}

(x - 0)^{2} + (y - 20)^{2} = 400

y^{2} = x^{2} - 1

9 x^{2} + 16 y^{2} = 144

x^{2} = 4 y - 2 y^{2}

What is the axis (x^2)/(25)+(y^2)/(16)=1 ?
The axis (x^2)/(25)+(y^2)/(16)=1 is semi-major axis a=5, semi-minor axis b=4