What is the circumference (x-0)^2+(y-20)^2=400 ?

The circumference (x-0)^2+(y-20)^2=400 is C=40pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference (x-0)^2+(y-20)^2=400

circumference

(x - 0)^{2} + (y - 20)^{2} = 400

C = 40 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 0)^{2} + (y - 20)^{2} = 400 : r = 20

C = 2 π 20

Refine

C = 40 π

y^{2} = x^{2} - 1

9 x^{2} + 16 y^{2} = 144

x^{2} = 4 y - 2 y^{2}

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

What is the circumference (x-0)^2+(y-20)^2=400 ?
The circumference (x-0)^2+(y-20)^2=400 is C=40pi