What is 9x^2+9y^2+18x-18y+14=0 ?

The solution to 9x^2+9y^2+18x-18y+14=0 is Circle with (a,b)=(-1,1),r= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9x^2+9y^2+18x-18y+14=0

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

(a, b) = (- 1, 1), r = \frac{2}{3}

Solution steps

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

Rewrite

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = \frac{2}{3}

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

4 y^{2} + 48 x - 20 y = 71

y^{2} + 4 x = 0

y^{2} = - 9 x

x^{2} + y^{2} = 36

What is 9x^2+9y^2+18x-18y+14=0 ?
The solution to 9x^2+9y^2+18x-18y+14=0 is Circle with (a,b)=(-1,1),r= 2/3