en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2+4x=0

Solution

y^{2} + 4 x = 0

Solution

(h, k) = (0, 0), p = - 1

Solution steps

y^{2} + 4 x = 0

Rewrite

y^{2} + 4 x = 0

in the standard form:

4 (- 1) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 1

Popular Examples

foci y^2=-9x foci

y^{2} = - 9 x

radius x^2+y^2=36 radius

x^{2} + y^{2} = 36

foci y=x^2 foci

y = x^{2}

vertices y^2=-12x vertices

y^{2} = - 12 x

foci x^2-y^2=25 foci

x^{2} - y^{2} = 25

Frequently Asked Questions (FAQ)

What is y^2+4x=0 ?
The solution to y^2+4x=0 is Parabola with (h,k)=(0,0),p=-1