What is the foci x^2-y^2=25 ?

The foci x^2-y^2=25 is (5sqrt(2),0),(-5sqrt(2),0)

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foci x^2-y^2=25

foci

x^{2} - y^{2} = 25

(52, 0), (- 52, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 25 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 5^{2} : 52

(0 + 52, 0), (0 - 52, 0)

Refine

(52, 0), (- 52, 0)

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

y^{2} = - \frac{1}{4} x

f (x) = x^{2} - 8 x + 7

y^{2} = 16 x

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1