What is the directrix y^2=16x ?

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directrix y^2=16x

directrix

y^{2} = 16 x

x = - 4

Solution steps

Rewrite

y^{2} = 16 x

in the standard form:

4 \cdot 4 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 4

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 4

Refine

x = - 4

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

y^{2} = - 24 x

y^{2} = x

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

x^{2} = 24 y