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vertices y^2=-12x

الحلّ

vertices

y^{2} = - 12 x

الحلّ

(h, k) = (0, 0), p = - 3

خطوات الحلّ

y^{2} = - 12 x

Rewrite

y^{2} = - 12 x

in the standard form:

4 (- 3) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 3

أمثلة شائعة

foci x^2-y^2=25 foci

x^{2} - y^{2} = 25

center x^2+y^2+6x-4y+3=0 center

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

y^{2} = - \frac{1}{4} x

vertices f(x)=x^2-8x+7 vertices

f (x) = x^{2} - 8 x + 7

directrix y^2=16x directrix

y^{2} = 16 x