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Popular >

foci y=x^2

Solution

foci

y = x^{2}

Solution

(0, \frac{1}{4})

Solution steps

Rewrite

y = x^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{4})

Refine

(0, \frac{1}{4})

Popular Examples

vertices y^2=-12x vertices

y^{2} = - 12 x

foci x^2-y^2=25 foci

x^{2} - y^{2} = 25

center x^2+y^2+6x-4y+3=0 center

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

y^{2} = - \frac{1}{4} x

vertices f(x)=x^2-8x+7 vertices

f (x) = x^{2} - 8 x + 7

Frequently Asked Questions (FAQ)

What is the foci y=x^2 ?
The foci y=x^2 is (0, 1/4)