foki y=x^2

Lösung

foki

y = x^{2}

(0, \frac{1}{4})

Schritte zur Lösung

Rewrite

y = x^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{4})

Fasse zusammen

(0, \frac{1}{4})

y^{2} = - 12 x

x^{2} - y^{2} = 25

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

y^{2} = - \frac{1}{4} x

f (x) = x^{2} - 8 x + 7