What is x^2-4x+y^2-2y=-2 ?

The solution to x^2-4x+y^2-2y=-2 is Circle with (a,b)=(2,1),r=sqrt(3)

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x^2-4x+y^2-2y=-2

x^{2} - 4 x + y^{2} - 2 y = - 2

(a, b) = (2, 1), r = 3

Solution steps

x^{2} - 4 x + y^{2} - 2 y = - 2

Rewrite

x^{2} - 4 x + y^{2} - 2 y = - 2

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 3

\frac{x ^{2}}{4} + \frac{y ^{2}}{64} = 1

\frac{( x - 7 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

y^{2} = 1 - x

x^{2} + y^{2} + 4 y - 60 = 0

What is x^2-4x+y^2-2y=-2 ?
The solution to x^2-4x+y^2-2y=-2 is Circle with (a,b)=(2,1),r=sqrt(3)