What is the center x^2+y^2-18x-14y+124=0 ?

The center x^2+y^2-18x-14y+124=0 is (9,7)

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center x^2+y^2-18x-14y+124=0

center

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

(9, 7)

Solution steps

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

Rewrite

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - 7)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (9, 7), r = 6

And the center is:

(9, 7)

y^{2} + 4 y + 8 x - 12 = 0

13 x^{2} + 49 y^{2} = 637

4 x^{2} + 9 y^{2} = 36

x^{2} + \frac{y ^{2}}{16} = 1

y^{2} + 2 x^{2} = 1

What is the center x^2+y^2-18x-14y+124=0 ?
The center x^2+y^2-18x-14y+124=0 is (9,7)