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Popular >

vertices 4x^2+9y^2=36

Solution

vertices

4 x^{2} + 9 y^{2} = 36

Solution

(3, 0), (- 3, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} = 36 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 2

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

Popular Examples

vertices x^2+(y^2)/(16)=1 vertices

x^{2} + \frac{y ^{2}}{16} = 1

y^{2} + 2 x^{2} = 1

asymptotes of ((y+3)^2)/9-((x-2)^2)/(16)=1 asymptotes

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

y^2-10y-12x+37=0

y^{2} - 10 y - 12 x + 37 = 0

(x^2)/(a^2)-(y^2)/(b^2)=1

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

Frequently Asked Questions (FAQ)

What is the vertices 4x^2+9y^2=36 ?
The vertices 4x^2+9y^2=36 is (3,0),(-3,0)